Ufumbuzi - Tiger algebra Suluhishaji

1, 699

1,699

Maelezo kwa hatua

${(6 A 3)}_{16} = b a s e 10$

$6 A 3$ , $16$ , $10$ .

${(6 A 3)}_{16} = 6 \cdot 16^{2} + 10 \cdot 16^{1} + 3 \cdot 16^{0}$

$6 \cdot 16^{2} + 10 \cdot 16^{1} + 3 \cdot 16^{0} = 1699$

Hatua: $6 \cdot 16^{2}$
+ $10 \cdot 16^{1}$
+ $3 \cdot 16^{0}$ = $1, 699$ .

$\frac{1699}{10} = 169 r e m a \in d e r 9$

$\frac{169}{10} = 16 r e m a \in d e r 9$

$\frac{16}{10} = 1 r e m a \in d e r 6$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$9 \to 9 \to 6 \to 1 = 1699$

$1699 (b a s e 10) = {(1699)}_{10}$

$1, 699_{10} = 1, 699_{10}$ .

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