Ufumbuzi - Tiger algebra Suluhishaji

1, 495

1,495

Maelezo kwa hatua

${(5 D 7)}_{16} = b a s e 10$

$5 D 7$ , $16$ , $10$ .

${(5 D 7)}_{16} = 5 \cdot 16^{2} + 13 \cdot 16^{1} + 7 \cdot 16^{0}$

$5 \cdot 16^{2} + 13 \cdot 16^{1} + 7 \cdot 16^{0} = 1495$

Hatua: $5 \cdot 16^{2}$
+ $13 \cdot 16^{1}$
+ $7 \cdot 16^{0}$ = $1, 495$ .

$\frac{1495}{10} = 149 r e m a \in d e r 5$

$\frac{149}{10} = 14 r e m a \in d e r 9$

$\frac{14}{10} = 1 r e m a \in d e r 4$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$5 \to 9 \to 4 \to 1 = 1495$

$1495 (b a s e 10) = {(1495)}_{10}$

$1, 495_{10} = 1, 495_{10}$ .

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