Ufumbuzi - Tiger algebra Suluhishaji

1, 440

1,440

Maelezo kwa hatua

${(5 A 0)}_{16} = b a s e 10$

$5 A 0$ , $16$ , $10$ .

${(5 A 0)}_{16} = 5 \cdot 16^{2} + 10 \cdot 16^{1} + 0 \cdot 16^{0}$

$5 \cdot 16^{2} + 10 \cdot 16^{1} + 0 \cdot 16^{0} = 1440$

Hatua: $5 \cdot 16^{2}$
+ $10 \cdot 16^{1}$
+ $0 \cdot 16^{0}$ = $1, 440$ .

$\frac{1440}{10} = 144 r e m a \in d e r 0$

$\frac{144}{10} = 14 r e m a \in d e r 4$

$\frac{14}{10} = 1 r e m a \in d e r 4$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$0 \to 4 \to 4 \to 1 = 1440$

$1440 (b a s e 10) = {(1440)}_{10}$

$1, 440_{10} = 1, 440_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

Tulifanyaje?

Jifunze zaidi na Tiger

Ubadilishaji wa msingi ni wa msingi kwa sayansi ya kompyuta, mifumo ya kidijitali, na nadharia ya namba.