Ufumbuzi - Tiger algebra Suluhishaji

1, 269

1,269

Maelezo kwa hatua

${(4 F 5)}_{16} = b a s e 10$

$4 F 5$ , $16$ , $10$ .

${(4 F 5)}_{16} = 4 \cdot 16^{2} + 15 \cdot 16^{1} + 5 \cdot 16^{0}$

$4 \cdot 16^{2} + 15 \cdot 16^{1} + 5 \cdot 16^{0} = 1269$

Hatua: $4 \cdot 16^{2}$
+ $15 \cdot 16^{1}$
+ $5 \cdot 16^{0}$ = $1, 269$ .

$\frac{1269}{10} = 126 r e m a \in d e r 9$

$\frac{126}{10} = 12 r e m a \in d e r 6$

$\frac{12}{10} = 1 r e m a \in d e r 2$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$9 \to 6 \to 2 \to 1 = 1269$

$1269 (b a s e 10) = {(1269)}_{10}$

$1, 269_{10} = 1, 269_{10}$ .

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