Ufumbuzi - Tiger algebra Suluhishaji

1, 248

1,248

Maelezo kwa hatua

${(4 E 0)}_{16} = b a s e 10$

$4 E 0$ , $16$ , $10$ .

${(4 E 0)}_{16} = 4 \cdot 16^{2} + 14 \cdot 16^{1} + 0 \cdot 16^{0}$

$4 \cdot 16^{2} + 14 \cdot 16^{1} + 0 \cdot 16^{0} = 1248$

Hatua: $4 \cdot 16^{2}$
+ $14 \cdot 16^{1}$
+ $0 \cdot 16^{0}$ = $1, 248$ .

$\frac{1248}{10} = 124 r e m a \in d e r 8$

$\frac{124}{10} = 12 r e m a \in d e r 4$

$\frac{12}{10} = 1 r e m a \in d e r 2$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$8 \to 4 \to 2 \to 1 = 1248$

$1248 (b a s e 10) = {(1248)}_{10}$

$1, 248_{10} = 1, 248_{10}$ .

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