Ufumbuzi - Tiger algebra Suluhishaji

1, 233

1,233

Maelezo kwa hatua

${(4 D 1)}_{16} = b a s e 10$

$4 D 1$ , $16$ , $10$ .

${(4 D 1)}_{16} = 4 \cdot 16^{2} + 13 \cdot 16^{1} + 1 \cdot 16^{0}$

$4 \cdot 16^{2} + 13 \cdot 16^{1} + 1 \cdot 16^{0} = 1233$

Hatua: $4 \cdot 16^{2}$
+ $13 \cdot 16^{1}$
+ $1 \cdot 16^{0}$ = $1, 233$ .

$\frac{1233}{10} = 123 r e m a \in d e r 3$

$\frac{123}{10} = 12 r e m a \in d e r 3$

$\frac{12}{10} = 1 r e m a \in d e r 2$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$3 \to 3 \to 2 \to 1 = 1233$

$1233 (b a s e 10) = {(1233)}_{10}$

$1, 233_{10} = 1, 233_{10}$ .

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