Ufumbuzi - Tiger algebra Suluhishaji

1, 189

1,189

Maelezo kwa hatua

${(4 A 5)}_{16} = b a s e 10$

$4 A 5$ , $16$ , $10$ .

${(4 A 5)}_{16} = 4 \cdot 16^{2} + 10 \cdot 16^{1} + 5 \cdot 16^{0}$

$4 \cdot 16^{2} + 10 \cdot 16^{1} + 5 \cdot 16^{0} = 1189$

Hatua: $4 \cdot 16^{2}$
+ $10 \cdot 16^{1}$
+ $5 \cdot 16^{0}$ = $1, 189$ .

$\frac{1189}{10} = 118 r e m a \in d e r 9$

$\frac{118}{10} = 11 r e m a \in d e r 8$

$\frac{11}{10} = 1 r e m a \in d e r 1$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$9 \to 8 \to 1 \to 1 = 1189$

$1189 (b a s e 10) = {(1189)}_{10}$

$1, 189_{10} = 1, 189_{10}$ .

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