Ufumbuzi - Tiger algebra Suluhishaji

737

737

Maelezo kwa hatua

${(2 E 1)}_{16} = b a s e 10$

$2 E 1$ , $16$ , $10$ .

${(2 E 1)}_{16} = 2 \cdot 16^{2} + 14 \cdot 16^{1} + 1 \cdot 16^{0}$

$2 \cdot 16^{2} + 14 \cdot 16^{1} + 1 \cdot 16^{0} = 737$

Hatua: $2 \cdot 16^{2}$
+ $14 \cdot 16^{1}$
+ $1 \cdot 16^{0}$ = $737$ .

$\frac{737}{10} = 73 r e m a \in d e r 7$

$\frac{73}{10} = 7 r e m a \in d e r 3$

$\frac{7}{10} = 0 r e m a \in d e r 7$

$7 \to 3 \to 7 = 737$

$737 (b a s e 10) = {(737)}_{10}$

$737_{10} = 737_{10}$ .

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