Ufumbuzi - Tiger algebra Suluhishaji

728

728

Maelezo kwa hatua

${(2 D 8)}_{16} = b a s e 10$

$2 D 8$ , $16$ , $10$ .

${(2 D 8)}_{16} = 2 \cdot 16^{2} + 13 \cdot 16^{1} + 8 \cdot 16^{0}$

$2 \cdot 16^{2} + 13 \cdot 16^{1} + 8 \cdot 16^{0} = 728$

Hatua: $2 \cdot 16^{2}$
+ $13 \cdot 16^{1}$
+ $8 \cdot 16^{0}$ = $728$ .

$\frac{728}{10} = 72 r e m a \in d e r 8$

$\frac{72}{10} = 7 r e m a \in d e r 2$

$\frac{7}{10} = 0 r e m a \in d e r 7$

$8 \to 2 \to 7 = 728$

$728 (b a s e 10) = {(728)}_{10}$

$728_{10} = 728_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

Tulifanyaje?

Jifunze zaidi na Tiger

Ubadilishaji wa msingi ni wa msingi kwa sayansi ya kompyuta, mifumo ya kidijitali, na nadharia ya namba.