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Ufumbuzi - Tiger algebra Suluhishaji

707

707

Maelezo kwa hatua

${(2 C 3)}_{16} = b a s e 10$

$2 C 3$ , $16$ , $10$ .

${(2 C 3)}_{16}$

Hatua: $2 \cdot 16^{2}$
+ $12 \cdot 16^{1}$
+ $3 \cdot 16^{0}$ = $707$ .

$2 \cdot 16^{2} + 12 \cdot 16^{1} + 3 \cdot 16^{0}$

Hatua: $2 \cdot 16^{2}$
+ $12 \cdot 16^{1}$
+ $3 \cdot 16^{0}$ = $707$ .

$707$

Hatua: $2 \cdot 16^{2}$
+ $12 \cdot 16^{1}$
+ $3 \cdot 16^{0}$ = $707$ .

$707 (b a s e 10)$

$707_{10} = 707_{10}$ .

$\frac{707}{10}$

$707_{10} = 707_{10}$ .

$707 = 10 \cdot 70 + 7$

$707_{10} = 707_{10}$ .

$70 = 10 \cdot 7 + 0$

$707_{10} = 707_{10}$ .

$7 = 10 \cdot 0 + 7$

$707_{10} = 707_{10}$ .

$707$

$707_{10} = 707_{10}$ .

${(707)}_{10}$

$707_{10} = 707_{10}$ .

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