Ufumbuzi - Tiger algebra Suluhishaji

697

697

Maelezo kwa hatua

${(2 B 9)}_{16} = b a s e 10$

$2 B 9$ , $16$ , $10$ .

${(2 B 9)}_{16} = 2 \cdot 16^{2} + 11 \cdot 16^{1} + 9 \cdot 16^{0}$

$2 \cdot 16^{2} + 11 \cdot 16^{1} + 9 \cdot 16^{0} = 697$

Hatua: $2 \cdot 16^{2}$
+ $11 \cdot 16^{1}$
+ $9 \cdot 16^{0}$ = $697$ .

$\frac{697}{10} = 69 r e m a \in d e r 7$

$\frac{69}{10} = 6 r e m a \in d e r 9$

$\frac{6}{10} = 0 r e m a \in d e r 6$

$7 \to 9 \to 6 = 697$

$697 (b a s e 10) = {(697)}_{10}$

$697_{10} = 697_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

Tulifanyaje?

Jifunze zaidi na Tiger

Ubadilishaji wa msingi ni wa msingi kwa sayansi ya kompyuta, mifumo ya kidijitali, na nadharia ya namba.