Ufumbuzi - Tiger algebra Suluhishaji

504

504

Maelezo kwa hatua

${(1 F 8)}_{16} = b a s e 10$

$1 F 8$ , $16$ , $10$ .

${(1 F 8)}_{16} = 1 \cdot 16^{2} + 15 \cdot 16^{1} + 8 \cdot 16^{0}$

$1 \cdot 16^{2} + 15 \cdot 16^{1} + 8 \cdot 16^{0} = 504$

Hatua: $1 \cdot 16^{2}$
+ $15 \cdot 16^{1}$
+ $8 \cdot 16^{0}$ = $504$ .

$\frac{504}{10} = 50 r e m a \in d e r 4$

$\frac{50}{10} = 5 r e m a \in d e r 0$

$\frac{5}{10} = 0 r e m a \in d e r 5$

$4 \to 0 \to 5 = 504$

$504 (b a s e 10) = {(504)}_{10}$

$504_{10} = 504_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

Tulifanyaje?

Jifunze zaidi na Tiger

Ubadilishaji wa msingi ni wa msingi kwa sayansi ya kompyuta, mifumo ya kidijitali, na nadharia ya namba.