Ufumbuzi - Tiger algebra Suluhishaji

438

438

Maelezo kwa hatua

${(1 B 6)}_{16} = b a s e 10$

$1 B 6$ , $16$ , $10$ .

${(1 B 6)}_{16} = 1 \cdot 16^{2} + 11 \cdot 16^{1} + 6 \cdot 16^{0}$

$1 \cdot 16^{2} + 11 \cdot 16^{1} + 6 \cdot 16^{0} = 438$

Hatua: $1 \cdot 16^{2}$
+ $11 \cdot 16^{1}$
+ $6 \cdot 16^{0}$ = $438$ .

$\frac{438}{10} = 43 r e m a \in d e r 8$

$\frac{43}{10} = 4 r e m a \in d e r 3$

$\frac{4}{10} = 0 r e m a \in d e r 4$

$8 \to 3 \to 4 = 438$

$438 (b a s e 10) = {(438)}_{10}$

$438_{10} = 438_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

Tulifanyaje?

Jifunze zaidi na Tiger

Ubadilishaji wa msingi ni wa msingi kwa sayansi ya kompyuta, mifumo ya kidijitali, na nadharia ya namba.