Ufumbuzi - Tiger algebra Suluhishaji

425

425

Maelezo kwa hatua

${(1 A 9)}_{16} = b a s e 10$

$1 A 9$ , $16$ , $10$ .

${(1 A 9)}_{16} = 1 \cdot 16^{2} + 10 \cdot 16^{1} + 9 \cdot 16^{0}$

$1 \cdot 16^{2} + 10 \cdot 16^{1} + 9 \cdot 16^{0} = 425$

Hatua: $1 \cdot 16^{2}$
+ $10 \cdot 16^{1}$
+ $9 \cdot 16^{0}$ = $425$ .

$\frac{425}{10} = 42 r e m a \in d e r 5$

$\frac{42}{10} = 4 r e m a \in d e r 2$

$\frac{4}{10} = 0 r e m a \in d e r 4$

$5 \to 2 \to 4 = 425$

$425 (b a s e 10) = {(425)}_{10}$

$425_{10} = 425_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

Tulifanyaje?

Jifunze zaidi na Tiger

Ubadilishaji wa msingi ni wa msingi kwa sayansi ya kompyuta, mifumo ya kidijitali, na nadharia ya namba.