Ufumbuzi - Tiger algebra Suluhishaji

422

422

Maelezo kwa hatua

${(1 A 6)}_{16} = b a s e 10$

$1 A 6$ , $16$ , $10$ .

${(1 A 6)}_{16} = 1 \cdot 16^{2} + 10 \cdot 16^{1} + 6 \cdot 16^{0}$

$1 \cdot 16^{2} + 10 \cdot 16^{1} + 6 \cdot 16^{0} = 422$

Hatua: $1 \cdot 16^{2}$
+ $10 \cdot 16^{1}$
+ $6 \cdot 16^{0}$ = $422$ .

$\frac{422}{10} = 42 r e m a \in d e r 2$

$\frac{42}{10} = 4 r e m a \in d e r 2$

$\frac{4}{10} = 0 r e m a \in d e r 4$

$2 \to 2 \to 4 = 422$

$422 (b a s e 10) = {(422)}_{10}$

$422_{10} = 422_{10}$ .

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