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Ufumbuzi - Tiger algebra Suluhishaji

187260.90

187260.90

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9967, 13, 1, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 967$ , $r = 13 %$ , $n = 1$ , $t = 24$ .

$c i (9967, 13, 1, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 967$ , $r = 13 %$ , $n = 1$ , $t = 24$ .

$P = 9967, r = 13 %, n = 1, t = 24$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 967$ , $r = 13 %$ , $n = 1$ , $t = 24$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 967$ , $r = 13 %$ , $n = 1$ , $t = 24$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 967$ , $r = 13 %$ , $n = 1$ , $t = 24$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.13$

$n t = 24$

${(1 + r / n)}^{(n t)}$

$r / n = 0.13, n t = 24, {(1 + r / n)}^{(n t)} = 18.7880905061$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.13)}^{24} = 18.7880905061$

$r / n = 0.13, n t = 24, {(1 + r / n)}^{(n t)} = 18.7880905061$ .

$18.7880905061$

$r / n = 0.13, n t = 24, {(1 + r / n)}^{(n t)} = 18.7880905061$ .

3. Hesabu kiasi cha mwisho

$A = 187260.90$

$187260.90$

$9, 967 \cdot 18.7880905061 = 187260.90$ .

$187260.90$

$9, 967 \cdot 18.7880905061 = 187260.90$ .

$187260.90$

$9, 967 \cdot 18.7880905061 = 187260.90$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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