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Ufumbuzi - Tiger algebra Suluhishaji

106392.11

106392.11

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9883, 8, 4, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 883$ , $r = 8 %$ , $n = 4$ , $t = 30$ .

$c i (9883, 8, 4, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 883$ , $r = 8 %$ , $n = 4$ , $t = 30$ .

$P = 9883, r = 8 %, n = 4, t = 30$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 883$ , $r = 8 %$ , $n = 4$ , $t = 30$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 883$ , $r = 8 %$ , $n = 4$ , $t = 30$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 883$ , $r = 8 %$ , $n = 4$ , $t = 30$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 120$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 120, {(1 + r / n)}^{(n t)} = 10.7651630342$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{120} = 10.7651630342$

$r / n = 0.02, n t = 120, {(1 + r / n)}^{(n t)} = 10.7651630342$ .

$10.7651630342$

$r / n = 0.02, n t = 120, {(1 + r / n)}^{(n t)} = 10.7651630342$ .

3. Hesabu kiasi cha mwisho

$A = 106392.11$

$106392.11$

$9, 883 \cdot 10.7651630342 = 106392.11$ .

$106392.11$

$9, 883 \cdot 10.7651630342 = 106392.11$ .

$106392.11$

$9, 883 \cdot 10.7651630342 = 106392.11$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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