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Ufumbuzi - Tiger algebra Suluhishaji

261470.19

261470.19

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9881, 14, 1, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 881$ , $r = 14 %$ , $n = 1$ , $t = 25$ .

$c i (9881, 14, 1, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 881$ , $r = 14 %$ , $n = 1$ , $t = 25$ .

$P = 9881, r = 14 %, n = 1, t = 25$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 881$ , $r = 14 %$ , $n = 1$ , $t = 25$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 881$ , $r = 14 %$ , $n = 1$ , $t = 25$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 881$ , $r = 14 %$ , $n = 1$ , $t = 25$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.14$

$n t = 25$

${(1 + r / n)}^{(n t)}$

$r / n = 0.14, n t = 25, {(1 + r / n)}^{(n t)} = 26.4619158123$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.14)}^{25} = 26.4619158123$

$r / n = 0.14, n t = 25, {(1 + r / n)}^{(n t)} = 26.4619158123$ .

$26.4619158123$

$r / n = 0.14, n t = 25, {(1 + r / n)}^{(n t)} = 26.4619158123$ .

3. Hesabu kiasi cha mwisho

$A = 261470.19$

$261470.19$

$9, 881 \cdot 26.4619158123 = 261470.19$ .

$261470.19$

$9, 881 \cdot 26.4619158123 = 261470.19$ .

$261470.19$

$9, 881 \cdot 26.4619158123 = 261470.19$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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