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Ufumbuzi - Tiger algebra Suluhishaji

20773.67

20773.67

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9817, 11, 2, 7)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 817$ , $r = 11 %$ , $n = 2$ , $t = 7$ .

$c i (9817, 11, 2, 7)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 817$ , $r = 11 %$ , $n = 2$ , $t = 7$ .

$P = 9817, r = 11 %, n = 2, t = 7$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 817$ , $r = 11 %$ , $n = 2$ , $t = 7$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 817$ , $r = 11 %$ , $n = 2$ , $t = 7$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 817$ , $r = 11 %$ , $n = 2$ , $t = 7$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.055$

$n t = 14$

${(1 + r / n)}^{(n t)}$

$r / n = 0.055, n t = 14, {(1 + r / n)}^{(n t)} = 2.1160914618$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.055)}^{14} = 2.1160914618$

$r / n = 0.055, n t = 14, {(1 + r / n)}^{(n t)} = 2.1160914618$ .

$2.1160914618$

$r / n = 0.055, n t = 14, {(1 + r / n)}^{(n t)} = 2.1160914618$ .

3. Hesabu kiasi cha mwisho

$A = 20773.67$

$20773.67$

$9, 817 \cdot 2.1160914618 = 20773.67$ .

$20773.67$

$9, 817 \cdot 2.1160914618 = 20773.67$ .

$20773.67$

$9, 817 \cdot 2.1160914618 = 20773.67$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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