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Ufumbuzi - Tiger algebra Suluhishaji

76959.02

76959.02

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9728, 9, 1, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 728$ , $r = 9 %$ , $n = 1$ , $t = 24$ .

$c i (9728, 9, 1, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 728$ , $r = 9 %$ , $n = 1$ , $t = 24$ .

$P = 9728, r = 9 %, n = 1, t = 24$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 728$ , $r = 9 %$ , $n = 1$ , $t = 24$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 728$ , $r = 9 %$ , $n = 1$ , $t = 24$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 728$ , $r = 9 %$ , $n = 1$ , $t = 24$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.09$

$n t = 24$

${(1 + r / n)}^{(n t)}$

$r / n = 0.09, n t = 24, {(1 + r / n)}^{(n t)} = 7.9110831747$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.09)}^{24} = 7.9110831747$

$r / n = 0.09, n t = 24, {(1 + r / n)}^{(n t)} = 7.9110831747$ .

$7.9110831747$

$r / n = 0.09, n t = 24, {(1 + r / n)}^{(n t)} = 7.9110831747$ .

3. Hesabu kiasi cha mwisho

$A = 76959.02$

$76959.02$

$9, 728 \cdot 7.9110831747 = 76959.02$ .

$76959.02$

$9, 728 \cdot 7.9110831747 = 76959.02$ .

$76959.02$

$9, 728 \cdot 7.9110831747 = 76959.02$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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