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Ufumbuzi - Tiger algebra Suluhishaji

28348.93

28348.93

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9716, 11, 2, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 716$ , $r = 11 %$ , $n = 2$ , $t = 10$ .

$c i (9716, 11, 2, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 716$ , $r = 11 %$ , $n = 2$ , $t = 10$ .

$P = 9716, r = 11 %, n = 2, t = 10$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 716$ , $r = 11 %$ , $n = 2$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 716$ , $r = 11 %$ , $n = 2$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 716$ , $r = 11 %$ , $n = 2$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.055$

$n t = 20$

${(1 + r / n)}^{(n t)}$

$r / n = 0.055, n t = 20, {(1 + r / n)}^{(n t)} = 2.9177574906$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.055)}^{20} = 2.9177574906$

$r / n = 0.055, n t = 20, {(1 + r / n)}^{(n t)} = 2.9177574906$ .

$2.9177574906$

$r / n = 0.055, n t = 20, {(1 + r / n)}^{(n t)} = 2.9177574906$ .

3. Hesabu kiasi cha mwisho

$A = 28348.93$

$28348.93$

$9, 716 \cdot 2.9177574906 = 28348.93$ .

$28348.93$

$9, 716 \cdot 2.9177574906 = 28348.93$ .

$28348.93$

$9, 716 \cdot 2.9177574906 = 28348.93$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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