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Ufumbuzi - Tiger algebra Suluhishaji

20437.40

20437.40

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9669, 5, 12, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 669$ , $r = 5 %$ , $n = 12$ , $t = 15$ .

$c i (9669, 5, 12, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 669$ , $r = 5 %$ , $n = 12$ , $t = 15$ .

$P = 9669, r = 5 %, n = 12, t = 15$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 669$ , $r = 5 %$ , $n = 12$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 669$ , $r = 5 %$ , $n = 12$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 669$ , $r = 5 %$ , $n = 12$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0041666667$

$n t = 180$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0041666667, n t = 180, {(1 + r / n)}^{(n t)} = 2.1137039324$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0041666667)}^{180} = 2.1137039324$

$r / n = 0.0041666667, n t = 180, {(1 + r / n)}^{(n t)} = 2.1137039324$ .

$2.1137039324$

$r / n = 0.0041666667, n t = 180, {(1 + r / n)}^{(n t)} = 2.1137039324$ .

3. Hesabu kiasi cha mwisho

$A = 20437.40$

$20437.40$

$9, 669 \cdot 2.1137039324 = 20437.40$ .

$20437.40$

$9, 669 \cdot 2.1137039324 = 20437.40$ .

$20437.40$

$9, 669 \cdot 2.1137039324 = 20437.40$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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