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Ufumbuzi - Tiger algebra Suluhishaji

19616.05

19616.05

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9571, 8, 12, 9)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 571$ , $r = 8 %$ , $n = 12$ , $t = 9$ .

$c i (9571, 8, 12, 9)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 571$ , $r = 8 %$ , $n = 12$ , $t = 9$ .

$P = 9571, r = 8 %, n = 12, t = 9$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 571$ , $r = 8 %$ , $n = 12$ , $t = 9$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 571$ , $r = 8 %$ , $n = 12$ , $t = 9$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 571$ , $r = 8 %$ , $n = 12$ , $t = 9$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0066666667$

$n t = 108$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0066666667, n t = 108, {(1 + r / n)}^{(n t)} = 2.0495302358$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0066666667)}^{108} = 2.0495302358$

$r / n = 0.0066666667, n t = 108, {(1 + r / n)}^{(n t)} = 2.0495302358$ .

$2.0495302358$

$r / n = 0.0066666667, n t = 108, {(1 + r / n)}^{(n t)} = 2.0495302358$ .

3. Hesabu kiasi cha mwisho

$A = 19616.05$

$19616.05$

$9, 571 \cdot 2.0495302358 = 19616.05$ .

$19616.05$

$9, 571 \cdot 2.0495302358 = 19616.05$ .

$19616.05$

$9, 571 \cdot 2.0495302358 = 19616.05$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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