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Ufumbuzi - Tiger algebra Suluhishaji

314869.78

314869.78

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9565, 15, 1, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 565$ , $r = 15 %$ , $n = 1$ , $t = 25$ .

$c i (9565, 15, 1, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 565$ , $r = 15 %$ , $n = 1$ , $t = 25$ .

$P = 9565, r = 15 %, n = 1, t = 25$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 565$ , $r = 15 %$ , $n = 1$ , $t = 25$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 565$ , $r = 15 %$ , $n = 1$ , $t = 25$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 565$ , $r = 15 %$ , $n = 1$ , $t = 25$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.15$

$n t = 25$

${(1 + r / n)}^{(n t)}$

$r / n = 0.15, n t = 25, {(1 + r / n)}^{(n t)} = 32.9189526198$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.15)}^{25} = 32.9189526198$

$r / n = 0.15, n t = 25, {(1 + r / n)}^{(n t)} = 32.9189526198$ .

$32.9189526198$

$r / n = 0.15, n t = 25, {(1 + r / n)}^{(n t)} = 32.9189526198$ .

3. Hesabu kiasi cha mwisho

$A = 314869.78$

$314869.78$

$9, 565 \cdot 32.9189526198 = 314869.78$ .

$314869.78$

$9, 565 \cdot 32.9189526198 = 314869.78$ .

$314869.78$

$9, 565 \cdot 32.9189526198 = 314869.78$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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