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Ufumbuzi - Tiger algebra Suluhishaji

17837.94

17837.94

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9409, 13, 4, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 409$ , $r = 13 %$ , $n = 4$ , $t = 5$ .

$c i (9409, 13, 4, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 409$ , $r = 13 %$ , $n = 4$ , $t = 5$ .

$P = 9409, r = 13 %, n = 4, t = 5$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 409$ , $r = 13 %$ , $n = 4$ , $t = 5$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 409$ , $r = 13 %$ , $n = 4$ , $t = 5$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 409$ , $r = 13 %$ , $n = 4$ , $t = 5$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0325$

$n t = 20$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0325, n t = 20, {(1 + r / n)}^{(n t)} = 1.895837924$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0325)}^{20} = 1.895837924$

$r / n = 0.0325, n t = 20, {(1 + r / n)}^{(n t)} = 1.895837924$ .

$1.895837924$

$r / n = 0.0325, n t = 20, {(1 + r / n)}^{(n t)} = 1.895837924$ .

3. Hesabu kiasi cha mwisho

$A = 17837.94$

$17837.94$

$9, 409 \cdot 1.895837924 = 17837.94$ .

$17837.94$

$9, 409 \cdot 1.895837924 = 17837.94$ .

$17837.94$

$9, 409 \cdot 1.895837924 = 17837.94$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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