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Ufumbuzi - Tiger algebra Suluhishaji

20605.11

20605.11

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9330, 9, 2, 9)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 330$ , $r = 9 %$ , $n = 2$ , $t = 9$ .

$c i (9330, 9, 2, 9)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 330$ , $r = 9 %$ , $n = 2$ , $t = 9$ .

$P = 9330, r = 9 %, n = 2, t = 9$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 330$ , $r = 9 %$ , $n = 2$ , $t = 9$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 330$ , $r = 9 %$ , $n = 2$ , $t = 9$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 330$ , $r = 9 %$ , $n = 2$ , $t = 9$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.045$

$n t = 18$

${(1 + r / n)}^{(n t)}$

$r / n = 0.045, n t = 18, {(1 + r / n)}^{(n t)} = 2.2084787664$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.045)}^{18} = 2.2084787664$

$r / n = 0.045, n t = 18, {(1 + r / n)}^{(n t)} = 2.2084787664$ .

$2.2084787664$

$r / n = 0.045, n t = 18, {(1 + r / n)}^{(n t)} = 2.2084787664$ .

3. Hesabu kiasi cha mwisho

$A = 20605.11$

$20605.11$

$9, 330 \cdot 2.2084787664 = 20605.11$ .

$20605.11$

$9, 330 \cdot 2.2084787664 = 20605.11$ .

$20605.11$

$9, 330 \cdot 2.2084787664 = 20605.11$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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