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Ufumbuzi - Tiger algebra Suluhishaji

131287.48

131287.48

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9270, 15, 4, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 270$ , $r = 15 %$ , $n = 4$ , $t = 18$ .

$c i (9270, 15, 4, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 270$ , $r = 15 %$ , $n = 4$ , $t = 18$ .

$P = 9270, r = 15 %, n = 4, t = 18$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 270$ , $r = 15 %$ , $n = 4$ , $t = 18$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 270$ , $r = 15 %$ , $n = 4$ , $t = 18$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 270$ , $r = 15 %$ , $n = 4$ , $t = 18$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0375$

$n t = 72$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0375, n t = 72, {(1 + r / n)}^{(n t)} = 14.1626195105$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0375)}^{72} = 14.1626195105$

$r / n = 0.0375, n t = 72, {(1 + r / n)}^{(n t)} = 14.1626195105$ .

$14.1626195105$

$r / n = 0.0375, n t = 72, {(1 + r / n)}^{(n t)} = 14.1626195105$ .

3. Hesabu kiasi cha mwisho

$A = 131287.48$

$131287.48$

$9, 270 \cdot 14.1626195105 = 131287.48$ .

$131287.48$

$9, 270 \cdot 14.1626195105 = 131287.48$ .

$131287.48$

$9, 270 \cdot 14.1626195105 = 131287.48$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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