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Ufumbuzi - Tiger algebra Suluhishaji

14289.42

14289.42

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (9213, 2, 4, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 213$ , $r = 2 %$ , $n = 4$ , $t = 22$ .

$c i (9213, 2, 4, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 213$ , $r = 2 %$ , $n = 4$ , $t = 22$ .

$P = 9213, r = 2 %, n = 4, t = 22$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 213$ , $r = 2 %$ , $n = 4$ , $t = 22$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 213$ , $r = 2 %$ , $n = 4$ , $t = 22$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 9, 213$ , $r = 2 %$ , $n = 4$ , $t = 22$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 88$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 88, {(1 + r / n)}^{(n t)} = 1.5510058454$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{88} = 1.5510058454$

$r / n = 0.005, n t = 88, {(1 + r / n)}^{(n t)} = 1.5510058454$ .

$1.5510058454$

$r / n = 0.005, n t = 88, {(1 + r / n)}^{(n t)} = 1.5510058454$ .

3. Hesabu kiasi cha mwisho

$A = 14289.42$

$14289.42$

$9, 213 \cdot 1.5510058454 = 14289.42$ .

$14289.42$

$9, 213 \cdot 1.5510058454 = 14289.42$ .

$14289.42$

$9, 213 \cdot 1.5510058454 = 14289.42$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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