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Ufumbuzi - Tiger algebra Suluhishaji

10354.45

10354.45

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (8827, 2, 4, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 827$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

$c i (8827, 2, 4, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 827$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

$P = 8827, r = 2 %, n = 4, t = 8$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 827$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 827$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 827$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 32$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 32, {(1 + r / n)}^{(n t)} = 1.1730431187$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{32} = 1.1730431187$

$r / n = 0.005, n t = 32, {(1 + r / n)}^{(n t)} = 1.1730431187$ .

$1.1730431187$

$r / n = 0.005, n t = 32, {(1 + r / n)}^{(n t)} = 1.1730431187$ .

3. Hesabu kiasi cha mwisho

$A = 10354.45$

$10354.45$

$8, 827 \cdot 1.1730431187 = 10354.45$ .

$10354.45$

$8, 827 \cdot 1.1730431187 = 10354.45$ .

$10354.45$

$8, 827 \cdot 1.1730431187 = 10354.45$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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