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Ufumbuzi - Tiger algebra Suluhishaji

10792.49

10792.49

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (8680, 2, 1, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 680$ , $r = 2 %$ , $n = 1$ , $t = 11$ .

$c i (8680, 2, 1, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 680$ , $r = 2 %$ , $n = 1$ , $t = 11$ .

$P = 8680, r = 2 %, n = 1, t = 11$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 680$ , $r = 2 %$ , $n = 1$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 680$ , $r = 2 %$ , $n = 1$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 680$ , $r = 2 %$ , $n = 1$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 11$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 11, {(1 + r / n)}^{(n t)} = 1.2433743084$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{11} = 1.2433743084$

$r / n = 0.02, n t = 11, {(1 + r / n)}^{(n t)} = 1.2433743084$ .

$1.2433743084$

$r / n = 0.02, n t = 11, {(1 + r / n)}^{(n t)} = 1.2433743084$ .

3. Hesabu kiasi cha mwisho

$A = 10792.49$

$10792.49$

$8, 680 \cdot 1.2433743084 = 10792.49$ .

$10792.49$

$8, 680 \cdot 1.2433743084 = 10792.49$ .

$10792.49$

$8, 680 \cdot 1.2433743084 = 10792.49$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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