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Ufumbuzi - Tiger algebra Suluhishaji

31077.40

31077.40

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (8529, 13, 12, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 529$ , $r = 13 %$ , $n = 12$ , $t = 10$ .

$c i (8529, 13, 12, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 529$ , $r = 13 %$ , $n = 12$ , $t = 10$ .

$P = 8529, r = 13 %, n = 12, t = 10$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 529$ , $r = 13 %$ , $n = 12$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 529$ , $r = 13 %$ , $n = 12$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 529$ , $r = 13 %$ , $n = 12$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0108333333$

$n t = 120$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0108333333, n t = 120, {(1 + r / n)}^{(n t)} = 3.6437332717$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0108333333)}^{120} = 3.6437332717$

$r / n = 0.0108333333, n t = 120, {(1 + r / n)}^{(n t)} = 3.6437332717$ .

$3.6437332717$

$r / n = 0.0108333333, n t = 120, {(1 + r / n)}^{(n t)} = 3.6437332717$ .

3. Hesabu kiasi cha mwisho

$A = 31077.40$

$31077.40$

$8, 529 \cdot 3.6437332717 = 31077.40$ .

$31077.40$

$8, 529 \cdot 3.6437332717 = 31077.40$ .

$31077.40$

$8, 529 \cdot 3.6437332717 = 31077.40$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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