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Ufumbuzi - Tiger algebra Suluhishaji

23349.14

23349.14

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (8338, 8, 4, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 338$ , $r = 8 %$ , $n = 4$ , $t = 13$ .

$c i (8338, 8, 4, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 338$ , $r = 8 %$ , $n = 4$ , $t = 13$ .

$P = 8338, r = 8 %, n = 4, t = 13$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 338$ , $r = 8 %$ , $n = 4$ , $t = 13$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 338$ , $r = 8 %$ , $n = 4$ , $t = 13$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 338$ , $r = 8 %$ , $n = 4$ , $t = 13$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 52$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 52, {(1 + r / n)}^{(n t)} = 2.8003281854$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{52} = 2.8003281854$

$r / n = 0.02, n t = 52, {(1 + r / n)}^{(n t)} = 2.8003281854$ .

$2.8003281854$

$r / n = 0.02, n t = 52, {(1 + r / n)}^{(n t)} = 2.8003281854$ .

3. Hesabu kiasi cha mwisho

$A = 23349.14$

$23349.14$

$8, 338 \cdot 2.8003281854 = 23349.14$ .

$23349.14$

$8, 338 \cdot 2.8003281854 = 23349.14$ .

$23349.14$

$8, 338 \cdot 2.8003281854 = 23349.14$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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