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Ufumbuzi - Tiger algebra Suluhishaji

11191.02

11191.02

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (8309, 3, 2, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 309$ , $r = 3 %$ , $n = 2$ , $t = 10$ .

$c i (8309, 3, 2, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 309$ , $r = 3 %$ , $n = 2$ , $t = 10$ .

$P = 8309, r = 3 %, n = 2, t = 10$

$\frac{3}{100} = 0.03$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 309$ , $r = 3 %$ , $n = 2$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 309$ , $r = 3 %$ , $n = 2$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 309$ , $r = 3 %$ , $n = 2$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.015$

$n t = 20$

${(1 + r / n)}^{(n t)}$

$r / n = 0.015, n t = 20, {(1 + r / n)}^{(n t)} = 1.3468550066$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.015)}^{20} = 1.3468550066$

$r / n = 0.015, n t = 20, {(1 + r / n)}^{(n t)} = 1.3468550066$ .

$1.3468550066$

$r / n = 0.015, n t = 20, {(1 + r / n)}^{(n t)} = 1.3468550066$ .

3. Hesabu kiasi cha mwisho

$A = 11191.02$

$11191.02$

$8, 309 \cdot 1.3468550066 = 11191.02$ .

$11191.02$

$8, 309 \cdot 1.3468550066 = 11191.02$ .

$11191.02$

$8, 309 \cdot 1.3468550066 = 11191.02$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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