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Ufumbuzi - Tiger algebra Suluhishaji

8716.05

8716.05

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (8292, 1, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 292$ , $r = 1 %$ , $n = 2$ , $t = 5$ .

$c i (8292, 1, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 292$ , $r = 1 %$ , $n = 2$ , $t = 5$ .

$P = 8292, r = 1 %, n = 2, t = 5$

$\frac{1}{100} = 0.01$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 292$ , $r = 1 %$ , $n = 2$ , $t = 5$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 292$ , $r = 1 %$ , $n = 2$ , $t = 5$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 8, 292$ , $r = 1 %$ , $n = 2$ , $t = 5$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 10$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 10, {(1 + r / n)}^{(n t)} = 1.051140132$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{10} = 1.051140132$

$r / n = 0.005, n t = 10, {(1 + r / n)}^{(n t)} = 1.051140132$ .

$1.051140132$

$r / n = 0.005, n t = 10, {(1 + r / n)}^{(n t)} = 1.051140132$ .

3. Hesabu kiasi cha mwisho

$A = 8716.05$

$8716.05$

$8, 292 \cdot 1.051140132 = 8716.05$ .

$8716.05$

$8, 292 \cdot 1.051140132 = 8716.05$ .

$8716.05$

$8, 292 \cdot 1.051140132 = 8716.05$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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