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Ufumbuzi - Tiger algebra Suluhishaji

463528.42

463528.42

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (7506, 15, 4, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 506$ , $r = 15 %$ , $n = 4$ , $t = 28$ .

$c i (7506, 15, 4, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 506$ , $r = 15 %$ , $n = 4$ , $t = 28$ .

$P = 7506, r = 15 %, n = 4, t = 28$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 506$ , $r = 15 %$ , $n = 4$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 506$ , $r = 15 %$ , $n = 4$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 506$ , $r = 15 %$ , $n = 4$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0375$

$n t = 112$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0375, n t = 112, {(1 + r / n)}^{(n t)} = 61.7543852848$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0375)}^{112} = 61.7543852848$

$r / n = 0.0375, n t = 112, {(1 + r / n)}^{(n t)} = 61.7543852848$ .

$61.7543852848$

$r / n = 0.0375, n t = 112, {(1 + r / n)}^{(n t)} = 61.7543852848$ .

3. Hesabu kiasi cha mwisho

$A = 463528.42$

$463528.42$

$7, 506 \cdot 61.7543852848 = 463528.42$ .

$463528.42$

$7, 506 \cdot 61.7543852848 = 463528.42$ .

$463528.42$

$7, 506 \cdot 61.7543852848 = 463528.42$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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