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Ufumbuzi - Tiger algebra Suluhishaji

412308.27

412308.27

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (7366, 15, 12, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 366$ , $r = 15 %$ , $n = 12$ , $t = 27$ .

$c i (7366, 15, 12, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 366$ , $r = 15 %$ , $n = 12$ , $t = 27$ .

$P = 7366, r = 15 %, n = 12, t = 27$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 366$ , $r = 15 %$ , $n = 12$ , $t = 27$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 366$ , $r = 15 %$ , $n = 12$ , $t = 27$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 366$ , $r = 15 %$ , $n = 12$ , $t = 27$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 324$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 324, {(1 + r / n)}^{(n t)} = 55.9745139739$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{324} = 55.9745139739$

$r / n = 0.0125, n t = 324, {(1 + r / n)}^{(n t)} = 55.9745139739$ .

$55.9745139739$

$r / n = 0.0125, n t = 324, {(1 + r / n)}^{(n t)} = 55.9745139739$ .

3. Hesabu kiasi cha mwisho

$A = 412308.27$

$412308.27$

$7, 366 \cdot 55.9745139739 = 412308.27$ .

$412308.27$

$7, 366 \cdot 55.9745139739 = 412308.27$ .

$412308.27$

$7, 366 \cdot 55.9745139739 = 412308.27$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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