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Ufumbuzi - Tiger algebra Suluhishaji

11139.64

11139.64

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (7240, 9, 1, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 240$ , $r = 9 %$ , $n = 1$ , $t = 5$ .

$c i (7240, 9, 1, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 240$ , $r = 9 %$ , $n = 1$ , $t = 5$ .

$P = 7240, r = 9 %, n = 1, t = 5$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 240$ , $r = 9 %$ , $n = 1$ , $t = 5$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 240$ , $r = 9 %$ , $n = 1$ , $t = 5$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 240$ , $r = 9 %$ , $n = 1$ , $t = 5$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.09$

$n t = 5$

${(1 + r / n)}^{(n t)}$

$r / n = 0.09, n t = 5, {(1 + r / n)}^{(n t)} = 1.5386239549$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.09)}^{5} = 1.5386239549$

$r / n = 0.09, n t = 5, {(1 + r / n)}^{(n t)} = 1.5386239549$ .

$1.5386239549$

$r / n = 0.09, n t = 5, {(1 + r / n)}^{(n t)} = 1.5386239549$ .

3. Hesabu kiasi cha mwisho

$A = 11139.64$

$11139.64$

$7, 240 \cdot 1.5386239549 = 11139.64$ .

$11139.64$

$7, 240 \cdot 1.5386239549 = 11139.64$ .

$11139.64$

$7, 240 \cdot 1.5386239549 = 11139.64$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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