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Ufumbuzi - Tiger algebra Suluhishaji

26504.21

26504.21

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (7219, 6, 2, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 219$ , $r = 6 %$ , $n = 2$ , $t = 22$ .

$c i (7219, 6, 2, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 219$ , $r = 6 %$ , $n = 2$ , $t = 22$ .

$P = 7219, r = 6 %, n = 2, t = 22$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 219$ , $r = 6 %$ , $n = 2$ , $t = 22$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 219$ , $r = 6 %$ , $n = 2$ , $t = 22$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 219$ , $r = 6 %$ , $n = 2$ , $t = 22$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 44$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 44, {(1 + r / n)}^{(n t)} = 3.6714522734$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{44} = 3.6714522734$

$r / n = 0.03, n t = 44, {(1 + r / n)}^{(n t)} = 3.6714522734$ .

$3.6714522734$

$r / n = 0.03, n t = 44, {(1 + r / n)}^{(n t)} = 3.6714522734$ .

3. Hesabu kiasi cha mwisho

$A = 26504.21$

$26504.21$

$7, 219 \cdot 3.6714522734 = 26504.21$ .

$26504.21$

$7, 219 \cdot 3.6714522734 = 26504.21$ .

$26504.21$

$7, 219 \cdot 3.6714522734 = 26504.21$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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