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Ufumbuzi - Tiger algebra Suluhishaji

8178.17

8178.17

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (7111, 1, 4, 14)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 111$ , $r = 1 %$ , $n = 4$ , $t = 14$ .

$c i (7111, 1, 4, 14)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 111$ , $r = 1 %$ , $n = 4$ , $t = 14$ .

$P = 7111, r = 1 %, n = 4, t = 14$

$\frac{1}{100} = 0.01$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 111$ , $r = 1 %$ , $n = 4$ , $t = 14$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 111$ , $r = 1 %$ , $n = 4$ , $t = 14$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 7, 111$ , $r = 1 %$ , $n = 4$ , $t = 14$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0025$

$n t = 56$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0025, n t = 56, {(1 + r / n)}^{(n t)} = 1.1500728534$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0025)}^{56} = 1.1500728534$

$r / n = 0.0025, n t = 56, {(1 + r / n)}^{(n t)} = 1.1500728534$ .

$1.1500728534$

$r / n = 0.0025, n t = 56, {(1 + r / n)}^{(n t)} = 1.1500728534$ .

3. Hesabu kiasi cha mwisho

$A = 8178.17$

$8178.17$

$7, 111 \cdot 1.1500728534 = 8178.17$ .

$8178.17$

$7, 111 \cdot 1.1500728534 = 8178.17$ .

$8178.17$

$7, 111 \cdot 1.1500728534 = 8178.17$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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