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Ufumbuzi - Tiger algebra Suluhishaji

22222.24

22222.24

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (6929, 6, 1, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 929$ , $r = 6 %$ , $n = 1$ , $t = 20$ .

$c i (6929, 6, 1, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 929$ , $r = 6 %$ , $n = 1$ , $t = 20$ .

$P = 6929, r = 6 %, n = 1, t = 20$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 929$ , $r = 6 %$ , $n = 1$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 929$ , $r = 6 %$ , $n = 1$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 929$ , $r = 6 %$ , $n = 1$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.06$

$n t = 20$

${(1 + r / n)}^{(n t)}$

$r / n = 0.06, n t = 20, {(1 + r / n)}^{(n t)} = 3.2071354722$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.06)}^{20} = 3.2071354722$

$r / n = 0.06, n t = 20, {(1 + r / n)}^{(n t)} = 3.2071354722$ .

$3.2071354722$

$r / n = 0.06, n t = 20, {(1 + r / n)}^{(n t)} = 3.2071354722$ .

3. Hesabu kiasi cha mwisho

$A = 22222.24$

$22222.24$

$6, 929 \cdot 3.2071354722 = 22222.24$ .

$22222.24$

$6, 929 \cdot 3.2071354722 = 22222.24$ .

$22222.24$

$6, 929 \cdot 3.2071354722 = 22222.24$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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