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Ufumbuzi - Tiger algebra Suluhishaji

14255.07

14255.07

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (6610, 6, 2, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 610$ , $r = 6 %$ , $n = 2$ , $t = 13$ .

$c i (6610, 6, 2, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 610$ , $r = 6 %$ , $n = 2$ , $t = 13$ .

$P = 6610, r = 6 %, n = 2, t = 13$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 610$ , $r = 6 %$ , $n = 2$ , $t = 13$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 610$ , $r = 6 %$ , $n = 2$ , $t = 13$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 610$ , $r = 6 %$ , $n = 2$ , $t = 13$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 26$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 26, {(1 + r / n)}^{(n t)} = 2.1565912675$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{26} = 2.1565912675$

$r / n = 0.03, n t = 26, {(1 + r / n)}^{(n t)} = 2.1565912675$ .

$2.1565912675$

$r / n = 0.03, n t = 26, {(1 + r / n)}^{(n t)} = 2.1565912675$ .

3. Hesabu kiasi cha mwisho

$A = 14255.07$

$14255.07$

$6, 610 \cdot 2.1565912675 = 14255.07$ .

$14255.07$

$6, 610 \cdot 2.1565912675 = 14255.07$ .

$14255.07$

$6, 610 \cdot 2.1565912675 = 14255.07$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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