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Ufumbuzi - Tiger algebra Suluhishaji

7867.28

7867.28

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (6509, 1, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 509$ , $r = 1 %$ , $n = 2$ , $t = 19$ .

$c i (6509, 1, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 509$ , $r = 1 %$ , $n = 2$ , $t = 19$ .

$P = 6509, r = 1 %, n = 2, t = 19$

$\frac{1}{100} = 0.01$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 509$ , $r = 1 %$ , $n = 2$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 509$ , $r = 1 %$ , $n = 2$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 509$ , $r = 1 %$ , $n = 2$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 38$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 38, {(1 + r / n)}^{(n t)} = 1.2086772471$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{38} = 1.2086772471$

$r / n = 0.005, n t = 38, {(1 + r / n)}^{(n t)} = 1.2086772471$ .

$1.2086772471$

$r / n = 0.005, n t = 38, {(1 + r / n)}^{(n t)} = 1.2086772471$ .

3. Hesabu kiasi cha mwisho

$A = 7867.28$

$7867.28$

$6, 509 \cdot 1.2086772471 = 7867.28$ .

$7867.28$

$6, 509 \cdot 1.2086772471 = 7867.28$ .

$7867.28$

$6, 509 \cdot 1.2086772471 = 7867.28$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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