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Ufumbuzi - Tiger algebra Suluhishaji

68383.49

68383.49

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (6484, 11, 2, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 484$ , $r = 11 %$ , $n = 2$ , $t = 22$ .

$c i (6484, 11, 2, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 484$ , $r = 11 %$ , $n = 2$ , $t = 22$ .

$P = 6484, r = 11 %, n = 2, t = 22$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 484$ , $r = 11 %$ , $n = 2$ , $t = 22$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 484$ , $r = 11 %$ , $n = 2$ , $t = 22$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 484$ , $r = 11 %$ , $n = 2$ , $t = 22$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.055$

$n t = 44$

${(1 + r / n)}^{(n t)}$

$r / n = 0.055, n t = 44, {(1 + r / n)}^{(n t)} = 10.5464967676$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.055)}^{44} = 10.5464967676$

$r / n = 0.055, n t = 44, {(1 + r / n)}^{(n t)} = 10.5464967676$ .

$10.5464967676$

$r / n = 0.055, n t = 44, {(1 + r / n)}^{(n t)} = 10.5464967676$ .

3. Hesabu kiasi cha mwisho

$A = 68383.49$

$68383.49$

$6, 484 \cdot 10.5464967676 = 68383.49$ .

$68383.49$

$6, 484 \cdot 10.5464967676 = 68383.49$ .

$68383.49$

$6, 484 \cdot 10.5464967676 = 68383.49$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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