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Ufumbuzi - Tiger algebra Suluhishaji

10912.74

10912.74

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (6268, 2, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 268$ , $r = 2 %$ , $n = 1$ , $t = 28$ .

$c i (6268, 2, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 268$ , $r = 2 %$ , $n = 1$ , $t = 28$ .

$P = 6268, r = 2 %, n = 1, t = 28$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 268$ , $r = 2 %$ , $n = 1$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 268$ , $r = 2 %$ , $n = 1$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 268$ , $r = 2 %$ , $n = 1$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 28, {(1 + r / n)}^{(n t)} = 1.7410242062$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{28} = 1.7410242062$

$r / n = 0.02, n t = 28, {(1 + r / n)}^{(n t)} = 1.7410242062$ .

$1.7410242062$

$r / n = 0.02, n t = 28, {(1 + r / n)}^{(n t)} = 1.7410242062$ .

3. Hesabu kiasi cha mwisho

$A = 10912.74$

$10912.74$

$6, 268 \cdot 1.7410242062 = 10912.74$ .

$10912.74$

$6, 268 \cdot 1.7410242062 = 10912.74$ .

$10912.74$

$6, 268 \cdot 1.7410242062 = 10912.74$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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