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Ufumbuzi - Tiger algebra Suluhishaji

16926.72

16926.72

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (6258, 4, 4, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 258$ , $r = 4 %$ , $n = 4$ , $t = 25$ .

$c i (6258, 4, 4, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 258$ , $r = 4 %$ , $n = 4$ , $t = 25$ .

$P = 6258, r = 4 %, n = 4, t = 25$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 258$ , $r = 4 %$ , $n = 4$ , $t = 25$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 258$ , $r = 4 %$ , $n = 4$ , $t = 25$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 258$ , $r = 4 %$ , $n = 4$ , $t = 25$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 100$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 100, {(1 + r / n)}^{(n t)} = 2.7048138294$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{100} = 2.7048138294$

$r / n = 0.01, n t = 100, {(1 + r / n)}^{(n t)} = 2.7048138294$ .

$2.7048138294$

$r / n = 0.01, n t = 100, {(1 + r / n)}^{(n t)} = 2.7048138294$ .

3. Hesabu kiasi cha mwisho

$A = 16926.72$

$16926.72$

$6, 258 \cdot 2.7048138294 = 16926.72$ .

$16926.72$

$6, 258 \cdot 2.7048138294 = 16926.72$ .

$16926.72$

$6, 258 \cdot 2.7048138294 = 16926.72$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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