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Ufumbuzi - Tiger algebra Suluhishaji

13581.73

13581.73

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (6133, 5, 4, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 133$ , $r = 5 %$ , $n = 4$ , $t = 16$ .

$c i (6133, 5, 4, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 133$ , $r = 5 %$ , $n = 4$ , $t = 16$ .

$P = 6133, r = 5 %, n = 4, t = 16$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 133$ , $r = 5 %$ , $n = 4$ , $t = 16$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 133$ , $r = 5 %$ , $n = 4$ , $t = 16$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 133$ , $r = 5 %$ , $n = 4$ , $t = 16$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 64$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 64, {(1 + r / n)}^{(n t)} = 2.2145324106$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{64} = 2.2145324106$

$r / n = 0.0125, n t = 64, {(1 + r / n)}^{(n t)} = 2.2145324106$ .

$2.2145324106$

$r / n = 0.0125, n t = 64, {(1 + r / n)}^{(n t)} = 2.2145324106$ .

3. Hesabu kiasi cha mwisho

$A = 13581.73$

$13581.73$

$6, 133 \cdot 2.2145324106 = 13581.73$ .

$13581.73$

$6, 133 \cdot 2.2145324106 = 13581.73$ .

$13581.73$

$6, 133 \cdot 2.2145324106 = 13581.73$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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