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Ufumbuzi - Tiger algebra Suluhishaji

22940.07

22940.07

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (6125, 9, 2, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 125$ , $r = 9 %$ , $n = 2$ , $t = 15$ .

$c i (6125, 9, 2, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 125$ , $r = 9 %$ , $n = 2$ , $t = 15$ .

$P = 6125, r = 9 %, n = 2, t = 15$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 125$ , $r = 9 %$ , $n = 2$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 125$ , $r = 9 %$ , $n = 2$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 125$ , $r = 9 %$ , $n = 2$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.045$

$n t = 30$

${(1 + r / n)}^{(n t)}$

$r / n = 0.045, n t = 30, {(1 + r / n)}^{(n t)} = 3.7453181345$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.045)}^{30} = 3.7453181345$

$r / n = 0.045, n t = 30, {(1 + r / n)}^{(n t)} = 3.7453181345$ .

$3.7453181345$

$r / n = 0.045, n t = 30, {(1 + r / n)}^{(n t)} = 3.7453181345$ .

3. Hesabu kiasi cha mwisho

$A = 22940.07$

$22940.07$

$6, 125 \cdot 3.7453181345 = 22940.07$ .

$22940.07$

$6, 125 \cdot 3.7453181345 = 22940.07$ .

$22940.07$

$6, 125 \cdot 3.7453181345 = 22940.07$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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