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Ufumbuzi - Tiger algebra Suluhishaji

237344.00

237344.00

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (6054, 14, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 054$ , $r = 14 %$ , $n = 1$ , $t = 28$ .

$c i (6054, 14, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 054$ , $r = 14 %$ , $n = 1$ , $t = 28$ .

$P = 6054, r = 14 %, n = 1, t = 28$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 054$ , $r = 14 %$ , $n = 1$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 054$ , $r = 14 %$ , $n = 1$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 6, 054$ , $r = 14 %$ , $n = 1$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.14$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.14, n t = 28, {(1 + r / n)}^{(n t)} = 39.2044926003$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.14)}^{28} = 39.2044926003$

$r / n = 0.14, n t = 28, {(1 + r / n)}^{(n t)} = 39.2044926003$ .

$39.2044926003$

$r / n = 0.14, n t = 28, {(1 + r / n)}^{(n t)} = 39.2044926003$ .

3. Hesabu kiasi cha mwisho

$A = 237344.00$

$237344.00$

$6, 054 \cdot 39.2044926003 = 237344.00$ .

$237344.00$

$6, 054 \cdot 39.2044926003 = 237344.00$ .

$237344.00$

$6, 054 \cdot 39.2044926003 = 237344.00$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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