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Ufumbuzi - Tiger algebra Suluhishaji

13503.35

13503.35

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (5902, 3, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 902$ , $r = 3 %$ , $n = 1$ , $t = 28$ .

$c i (5902, 3, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 902$ , $r = 3 %$ , $n = 1$ , $t = 28$ .

$P = 5902, r = 3 %, n = 1, t = 28$

$\frac{3}{100} = 0.03$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 902$ , $r = 3 %$ , $n = 1$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 902$ , $r = 3 %$ , $n = 1$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 902$ , $r = 3 %$ , $n = 1$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 28, {(1 + r / n)}^{(n t)} = 2.2879276757$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{28} = 2.2879276757$

$r / n = 0.03, n t = 28, {(1 + r / n)}^{(n t)} = 2.2879276757$ .

$2.2879276757$

$r / n = 0.03, n t = 28, {(1 + r / n)}^{(n t)} = 2.2879276757$ .

3. Hesabu kiasi cha mwisho

$A = 13503.35$

$13503.35$

$5, 902 \cdot 2.2879276757 = 13503.35$ .

$13503.35$

$5, 902 \cdot 2.2879276757 = 13503.35$ .

$13503.35$

$5, 902 \cdot 2.2879276757 = 13503.35$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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