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Ufumbuzi - Tiger algebra Suluhishaji

25572.21

25572.21

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (5632, 9, 4, 17)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 632$ , $r = 9 %$ , $n = 4$ , $t = 17$ .

$c i (5632, 9, 4, 17)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 632$ , $r = 9 %$ , $n = 4$ , $t = 17$ .

$P = 5632, r = 9 %, n = 4, t = 17$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 632$ , $r = 9 %$ , $n = 4$ , $t = 17$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 632$ , $r = 9 %$ , $n = 4$ , $t = 17$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 632$ , $r = 9 %$ , $n = 4$ , $t = 17$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0225$

$n t = 68$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0225, n t = 68, {(1 + r / n)}^{(n t)} = 4.5405193853$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0225)}^{68} = 4.5405193853$

$r / n = 0.0225, n t = 68, {(1 + r / n)}^{(n t)} = 4.5405193853$ .

$4.5405193853$

$r / n = 0.0225, n t = 68, {(1 + r / n)}^{(n t)} = 4.5405193853$ .

3. Hesabu kiasi cha mwisho

$A = 25572.21$

$25572.21$

$5, 632 \cdot 4.5405193853 = 25572.21$ .

$25572.21$

$5, 632 \cdot 4.5405193853 = 25572.21$ .

$25572.21$

$5, 632 \cdot 4.5405193853 = 25572.21$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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